Lake Alfred
Sign in to saveAlso known as Lake Alfred, Florida, Lake Alfred, FL
city in Polk County, Florida, United States of America
In the Vinony graph
Vinony's link graph records 255 inbound references to Lake Alfred, and connects out to race and ethnicity in the United States Census, Polk County and United States.
The entry is geolocated on the map in city.
It is catalogued under topics including Cities in Florida, Cities in Polk County, Florida and Populated places in the United States established in 1915.
Vinony links it to 36 Wikipedia language editions.
Key facts
- Country
- United States
- State
- Florida
- County
- Polk
- Total
- 13.10 sq mi (33.93 km )
- Land
- 9.20 sq mi (23.82 km )
- Water
- 3.90 sq mi (10.10 km )
- Elevation
- 131 ft (40 m)
- Density
- 692.9/sq mi (267.54/km )
- Time zone
- UTC-5 ( Eastern (EST) )
- Summer dst
- UTC-4 (EDT)
- Fips code
- 12-37525
- Website
- mylakealfred .com
via Wikipedia infobox
Wikidata facts
- Instance of
- city in the United States
- Official name
- Lake Alfred
- Country
- United States
- Located in
- Polk County
- Population
- 6374
- Area
- 34.128053
- Elevation
- 53
- Official website
- mylakealfred.com
- Households
- 2218
- Dialing code
- 863
Show 6 more facts
- Commons category
- Lake Alfred, Florida
- postal code
- 33850
- inception
- 1915-01-01
- P8168
- Gaillard
- water as percent of area
- 29.5819
- per capita income
- 24252
Sources (7)
via Wikidata · CC0
~8 min read
Encyclopedic overview
Lake Alfred is a city in Polk County, Florida, United States. It is part of the Lakeland–Winter Haven Metropolitan Statistical Area. The population was approximately 6,374 at the 2020 US census.
History
Excerpted from Wikipedia’s “Lake Alfred” article, available under the CC BY-SA 4.0 licence.